Duration 10:19

Quadrature Amplitude Modulation (QAM)/QAM Modulation/QAM Transmitter and Receiver/Block Diagram [HD]

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Published 27 May 2018

This video is about Quadrature Amplitude Modulation (QAM). Quadrature Amplitude Modulation (QAM) Transmitter and Receiver have been discussed here. You will get here the basic concept of QAM modulation and why it is called as Quadrature Amplitude Modulation. Block Diagrams of QAM transmitter and Receivers are also explained here. Quadrature Amplitude Modulation (QAM) is also called as bandwidth conservation scheme. In Quadrature Amplitude Modulation two carries are used in quadrature (phase shift of 90 degrees). QAM is a combination of AM and PM in analog case and ASK and PSK in digital case. Introduction of Quadrature Amplitude Modulation (QAM) Quadrature Amplitude Modulation (QAM) can be used, either with analog signals or digital signals. If the message signal is analog in nature, then we use it with Amplitude Modulation (AM) but when the message signal is in digital form, then Amplitude Shift Keying (ASK) is used. Using QAM, it is possible to transmit two analog message signals or two digital bit sequences by modulating carrier wave's amplitude using analog modulation technique (AM) or digital modulation technique. This modulation scheme is also known as 'Quadrature Carrier Multiplexing'. Now we will understand, what is the meaning of 'Quadrature' in Quadrature Amplitude Modulation (QAM). Actually in quadrature amplitude modulation, the two carrier waves are used, that are out of phase by 90 degrees. Therefore this scheme is known as quadrature amplitude modulation, and these carriers are known as Quadrature Carriers. These modulated waves are summed at the output of the transmitter, therefore the final waveform is the combination of both PSK and ASK in digital case or PM and AM for analogue case. Now we will understand this concept with the help of block diagrams of QAM Transmitter and QAM receiver. In this image, you can see that here we are transmitting two message signals of analog nature x1(t) and x2(t). Observe that it contains two product modulators. The inputs to the first product modulator is, message signal x1(t) and the carrier wave, while the inputs to the second product modulator are analogue message signal x2(t) and the carrier wave with a phase shift of 90 degrees. Here we have used a 90 degree phase shifter for phase shifting. Mathematical Representation of Multiplexed Signal s(t) Because we know, when the product modulator is supplied with a message signal and the carrier wave, then we get amplitude modulated wave in the output. So you can observe here that, quadrature amplitude modulation (QAM) is the combination of both Amplitude Modulation and phase modulation (As phase change of carrier wave takes place here). This was the case for analog modulation, but if we talk about QAM with digital modulation, then, at the place of analog message signal, we use digital messages. In this case it would be a combination of Amplitude Shift Keying (ASK) and Phase Shift Keying (PSK). Now see the Output of the QAM transmitter. Here the outputs of two product modulators are added and the resultant output is the multiplexed signal S(t). So this QAM scheme enables two modulated signals to occupy the same transmission channel and allows the separation of these two message signals at the receiver output therefore it is also known as 'Bandwidth Conservation Scheme'. With this scheme we are simultaneously transmitting two amplitude modulated waves (in case of analog modulation) or two amplitude shift keying signals (in case of digital modulation). Therefore this allows us to use the same transmission channel. And at the receiving end we can easily detect these message signals. Now it's time to discuss the block diagram of QAM receiver. As you can see here, block diagram contains 5 components... Two product modulators, one 90 degree phase shifter, and two low pass filters. Multiplexed signal S(t), which is output of the QAM transmitter, acts as the input to the QAM receiver. This multiplexed signal is applied to the inputs of both the product modulators. For the First product modulator therefore two inputs are- Multiplexed signal s(t) and the carrier wave while the inputs to the second product modulator are- multiplexed signal s(t) and the carrier wave with 90 degree phase shift. Now the outputs of these product modulators are passed through the Low Pass Filters (LPF) as depicted in the image. So at the outputs of these are low pass filters, we get the message signals. The oscillators used to produce carrier waves at the transmitting and receiving ends must be in coherence i.e. the carriers at the transmitting and receiving ends must be in same phase. In this way we get back the modulating signals x1(t) and x2(t)(message signals) at the receiving end. Visit My blog for more information https://www.engineeringmadeeasypro.com/ PLAYLIST: Communication Systems (Analog and Digital ) /playlist/PLDp9Jik5WjRuUyDT6961r8pkelgJMG8fG

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Comments - 176
  • @
    @chrisgraham82974 years ago I think the origin for noise would most often be the channel; however the biggest effect of noise would occur at the receiver after even the noise is amplified. 8
  • @
    @jessedavis61967 months ago So the multiplexed signal I am assuming are the data lines? But then you need an input for carrier signal as well right? I assume it would go to the modulator as well?
  • @
    @andrewheap30975 years ago As shown in Friis formula, the noise figure is primarily set by the noise figure of the transmitter 2
  • @
    @andreamendonca95535 years ago At the early stage, you have mentioned that the 2 carriers must be out of phase and at the end of the video you say they are in phase!! so which is right? 3
  • @
    @kailashsharma5996 years ago after the transmission at the channel when the transmitter sends the signal through the medium(channel) to the receiver
  • @
    @yusufgorkemmatyar21144 years ago Sir, QAM modulator transmitter capable of transmitting PAM signals ?
  • @
    @inakolluvenkatanarayana70103 years ago Yeah Channel has more Chance of Effecting the Noise! We eliminate Noise With Different Modulation Techniques such as AM, FM, PM
  • @
    @jaganmukesh42954 years ago please explain how we get 1/2Ax1(t) at the output of qam receiver 1
  • @
    @allenabishek1478last year is x(t) binary or a continuous signal?
  • @
    @ibrahimmilindi23465 years ago thank u so much , j'ai bien compris 2
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    @benjamingomado50645 years ago Noise is most likely at the transmitter 1
  • @
    @HarshYadav-kq2jt5 years ago Obviously sir in the channel or medium. 4
  • @
    @sukantosingh61934 years ago I can not understand receiver part, how to {1/2 An+t)} output value. 1
  • @
    @aleensafdar5135 years ago My answer is the Channel. 1
  • @
    @JamesHalpert85555 years ago noise most likely to occur in channel. 2
  • @
    @umakumari29596 years ago channel is prone to add most of the noise to the signal !! 2
  • @
    @gyajangithirupathi49875 years ago 1
  • @
    @demetriusdemarcusbartholom80632 years ago You are just reading things from a paper, not explaining.
  • @
    @chrisgraham82974 years ago I think the origin for noise would most often be the channel; however the biggest effect of noise would occur at the receiver after even the noise is amplified. 8
  • @
    @jessedavis61967 months ago So the multiplexed signal I am assuming are the data lines? But then you need an input for carrier signal as well right? I assume it would go to the modulator as well?
  • @
    @andrewheap30975 years ago As shown in Friis formula, the noise figure is primarily set by the noise figure of the transmitter 2
  • @
    @andreamendonca95535 years ago At the early stage, you have mentioned that the 2 carriers must be out of phase and at the end of the video you say they are in phase!! so which is right? 3
  • @
    @kailashsharma5996 years ago after the transmission at the channel when the transmitter sends the signal through the medium(channel) to the receiver
  • @
    @yusufgorkemmatyar21144 years ago Sir, QAM modulator transmitter capable of transmitting PAM signals ?
  • @
    @inakolluvenkatanarayana70103 years ago Yeah Channel has more Chance of Effecting the Noise! We eliminate Noise With Different Modulation Techniques such as AM, FM, PM
  • @
    @jaganmukesh42954 years ago please explain how we get 1/2Ax1(t) at the output of qam receiver 1
  • @
    @allenabishek1478last year is x(t) binary or a continuous signal?
  • @
    @ibrahimmilindi23465 years ago thank u so much , j'ai bien compris 2
  • @
    @benjamingomado50645 years ago Noise is most likely at the transmitter 1
  • @
    @HarshYadav-kq2jt5 years ago Obviously sir in the channel or medium. 4
  • @
    @sukantosingh61934 years ago I can not understand receiver part, how to {1/2 An+t)} output value. 1
  • @
    @aleensafdar5135 years ago My answer is the Channel. 1
  • @
    @JamesHalpert85555 years ago noise most likely to occur in channel. 2
  • @
    @umakumari29596 years ago channel is prone to add most of the noise to the signal !! 2
  • @
    @gyajangithirupathi49875 years ago 1
  • @
    @demetriusdemarcusbartholom80632 years ago You are just reading things from a paper, not explaining.